The roots of equation- x2-1-0- are

The correct option is D Has no rootsGiven: x2 + 1 = 0 ⇒ a= 1, b = 0, c = 1 Discriminant of the given quadratic equation is b2 4ac = 4 As the discrimina ...

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Question

The roots of equation, x² + 1 = 0, are

(1,1)

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(1, -1)

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(1,2)

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Has no roots

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Solution

The correct option is D Has no roots
Given: x² + 1 = 0 $\Rightarrow a = 1, b = 0, c = 1$

Discriminant of the given quadratic equation is b² - 4ac = -4

As the discriminant is negative, the equation does not have any real roots.

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The roots of equation, x2 + 1 = 0, are

The correct option is D Has no rootsGiven: x2 + 1 = 0 ⇒ a=1,b=0,c=1 Discriminant of the given quadratic equation is b2 - 4ac = -4 As the discriminant is negative, the equation does not have any real roots.

The roots of equation, x² + 1 = 0, are

The correct option is D Has no roots
Given: x² + 1 = 0 $\Rightarrow a = 1, b = 0, c = 1$

Discriminant of the given quadratic equation is b² - 4ac = -4

As the discriminant is negative, the equation does not have any real roots.