The roots of equation- x2-2-0- are

The correct option is D Not definedGiven: x2 + 2 = 0 ⇒ a = 1, b = 0, c = 2 Discriminant of the given quadratic equation is b2 4ac= ( 8) We know that if D ...

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Solving QE Using Quadratic Formula When D>0

The roots of ...

Question

The roots of equation, x² + 2 = 0, are

(2, -2)

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(2,3)

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(4,4)

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Not defined

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Solution

The correct option is D Not defined
Given: x² + 2 = 0 $\Rightarrow a = 1, b = 0, c = 2$

Discriminant of the given quadratic equation is b² - 4ac= (-8)

We know that if D < 0, the equation does not have real roots.

Therefore, the given equation has no real roots

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The roots of equation, x2 + 2 = 0, are

The correct option is D Not definedGiven: x2 + 2 = 0 ⇒ a=1,b=0,c=2 Discriminant of the given quadratic equation is b2 - 4ac= (-8) We know that if D < 0, the equation does not have real roots. Therefore, the given equation has no real roots

The roots of equation, x² + 2 = 0, are

The correct option is D Not defined
Given: x² + 2 = 0 $\Rightarrow a = 1, b = 0, c = 2$

Discriminant of the given quadratic equation is b² - 4ac= (-8)

We know that if D < 0, the equation does not have real roots.

Therefore, the given equation has no real roots