Question

The roots of $\sqrt{3}{x}^2+10x-8\sqrt{3}=0$ are

• A. $2\sqrt{3},4\sqrt{3}$
• B. $-2\sqrt{3},4\sqrt{3}$
• C. $2/\sqrt{3},-4\sqrt{3}$
• D. $-2\sqrt{3},-4\sqrt{3}$

Answer 1

The correct option is C $2/\sqrt{3},-4\sqrt{3}$

$\sqrt{3}{x}^2+10x-8\sqrt{3}=0$

$\Rightarrow$ $\sqrt{3}{x}^2+12x-2x-8\sqrt{3}=0$

$\Rightarrow$ $\sqrt{3}x(x+4\sqrt{3})-2(x+4\sqrt{3})=0$

$\Rightarrow$ $(\sqrt{3}x-2)(x+4\sqrt{3})=0$

$\Rightarrow$ $\sqrt{3}x-2=0$ and $x+4\sqrt{3}=0$

$\therefore$ $x=\frac{2}{\sqrt{3}}$ and $x=-4\sqrt{3}$