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Question

The roots of the equation 2x+227xx−1=9 are given by

A
1log23,2
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B
log23,1
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C
2,2
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D
2,1log3log2
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Solution

The correct option is C 2,2
2x+2.27xx1=9
or, 2x+2.33xx1=20.32
Comparing the powers of 2 and 3 both sides we get,
x=2 and 3xx1=2x=2.
Required roots are 2,2.

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