The roots of the equation (3−x)4+(2−x)4=(5−2x)4 are
2 real and 2 non real complex
Put a = 3-x, b = 2 -x a4+b4=(a+b)4
⇒ 2ab (2a2+3ab+2b2)=0
a = 0 (or) b = 0 (or) 2a2+3ab+2b2=0
i.e., 3-x = 0 or 2-x = 0 or 7x2−35x+44=0
solving we get x=3,x=2,x=(35± i √7)14