The roots of the equation 5x2 - 6x - 1 - 0 are- 5x2 - 6x - 1 - 0 - - -

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Relations between Roots and Coefficients : Higher Order Equations

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Question

The roots of the equation 5x² – 6x + 1 = 0 are

समीकरण 5x² – 6x + 1 = 0 के मूल हैं

x = 1, \frac{1}{5}

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x = - 1, \frac{- 1}{5}

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x = 1, \frac{- 1}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = - 1, \frac{1}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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\sqrt{5 x^{2} - 6 x + 8} - \sqrt{5 x^{2} - 6 x - 7} = 1

\sqrt{5 x^{2} - 6 x + 8} - \sqrt{5 x^{2} - 6 x - 7} = 1

If $α, β$ are the roots of the equation $2 x^{2} + 5 x + 6 = 0$ , then find the equation whose roots are $\frac{1}{α} a n d \frac{1}{β}$ .

5 x^{2} - 6 x - 2 = 0

\sqrt{5 x^{2} - 6 x + 8} - \sqrt{5 x^{2} - 6 x - 7} = 1

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