The roots of the equation a2 x2-a b x-b2- where a-0- are-

The correct option is D None of thesea^2 x^2 + abx = b^2 ( ax + b/2 )^2 = 5b^2/4 ax + b/2 = ±b/4 If b=0, then the roots will be real and equal, otherwise the ...

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The roots of the equation $a^{2} x^{2} + a b x = b^{2},$ where a $\neq$ 0, are:

Real but unequal

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Real but equal

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Not real

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None of these

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Solution

The correct option is D None of these
$a^{2} x^{2} + a b x = b^{2} {(a x + \frac{b}{2})}^{2} = \frac{5 b^{2}}{4} a x + \frac{b}{2} = \pm \frac{b}{4}$
If b=0, then the roots will be real and equal, otherwise they will be real and unequal.
Hence, option (d) is correct.

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The roots of the equation a2x2+abx=b2, where a ≠ 0, are:

The correct option is D None of thesea2x2+abx=b2(ax+b2)2=5b24ax+b2=±b4 If b=0, then the roots will be real and equal, otherwise they will be real and unequal. Hence, option (d) is correct.

The roots of the equation $a^{2} x^{2} + a b x = b^{2},$ where a $\neq$ 0, are:

The correct option is D None of these
$a^{2} x^{2} + a b x = b^{2} {(a x + \frac{b}{2})}^{2} = \frac{5 b^{2}}{4} a x + \frac{b}{2} = \pm \frac{b}{4}$
If b=0, then the roots will be real and equal, otherwise they will be real and unequal.
Hence, option (d) is correct.