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Question

The roots of the equation (c2−ab)x2−2(a2−bc)x+(b2−ac)=0 are equal then

A
a3+b3+c3=3abc or a=0
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B
a+b+c=0
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C
a3+b3+c3=3abc or a=1
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D
none of these
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Solution

The correct option is A a3+b3+c3=3abc or a=0
4(c2ab)x22(a2bc)x+(b2ac)=0
root are equal so D = 0
4(a2bc)24(c2ab)(b2ac)=0a42a2bc+b2c2(b2c2ab3ac3=0a(a3+b3+c33abc)=0a=0ora3+b3+c3=3abc


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