The correct option is D irrational and distinct.
1x+1+2x−4=2⇒x−4+2x+2(x+1)(x−4)=2⇒3x−2(x+1)(x−4)=2
Assuming x≠−1,4
⇒3x−2=2(x+1)(x−4)⇒3x−2=2x2−6x−8⇒2x2−9x−6=0
D=81+48=129
D is positive and not a perfect square.
Hence, roots are irrational and distinct.