wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The roots of the equation x2+Ax+B=0 are 5 and 4. The roots of x2+Cx+D=0 are 2 and 9. Which of the following is a root of x2+Ax+D=0?

A
3 & 9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6 & 3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6 & 9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3 & 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6 & 3
Let α,β be the roots of x2+Ax+B=0.
So, α+β=A=9αβ=B=20

Let γ,δ be the roots of x2+Cx+D=0.
So, γ+δ=C=11γδ=D=18

x2+Ax+D=0x29x+18=0x26x3x+18=0x(x6)3(x6)=0(x3)(x6)=0x=3,6
Hence option B.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Conjugate of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon