The correct option is B 1
For the given equation, let the roots be a,a+1
So sum of roots =a+a+1=2a+1=−−p1=p
Product of roots =a×(a+1)=a2+a=q1=q
For an equation ax2+bx+c=0, the discriminant is b2−4ac.
For the given eqn, the discriminant is (−p)2−4×1×q=(2a+1)2−4(a2+a)=4a2+1+4a−4a2−4a=1