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Question

The roots of the equation x2−px+q=0 are consecutive integers. Find the discriminate of the equation.

A
1
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B
0
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C
1
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D
None of these
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Solution

The correct option is B 1
For the given equation, let the roots be a,a+1
So sum of roots =a+a+1=2a+1=p1=p
Product of roots =a×(a+1)=a2+a=q1=q
For an equation ax2+bx+c=0, the discriminant is b24ac.
For the given eqn, the discriminant is (p)24×1×q=(2a+1)24(a2+a)=4a2+1+4a4a24a=1

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