Question

The roots of the equation $\frac{1}{a+b+x}=\left(\frac{1}{a}\right)+\left(\frac{1}{b}\right)+\left(\frac{1}{x}\right)$ are?

• A.
• B.
• C. -a ,-b
• D. (a-b), (a+b)

Answer 1

The correct option is C -a ,-b

Take a=1 and b=1, we basically need to find the value of x. now, the equation becomes $\frac{1}{(2+x)}=2+\frac{1}{x}$

$x^2+2x+1=0$ solving for x, we get x=-1,-1

Which is nothing but -a,-b. option c is the answer