The roots of the equation ix2−4x−4i = 0 are
2 ,-2i
2i
-2i, -2i
2i, 2i
we have ix2−4x−4i = 0
⇒x2+4ix−4 = 0 ⇒ x2+2ix+2ix−4 = 0
⇒ (x + 2i)(x + 2i) = 0 ⇒ x = -2i, -2i
Solve the quadratic equation ix2 – 3x - 2i = 0
Express the following in standard form: (8 – 4i)-(-2 – 3i)+(-10 + 3i)