The roots of the equation (p−2)x2+2(p−2)x+2=0 are not real when
A
p∈[1,2]
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B
p∈[2,3]
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C
p∈(2,4)
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D
p∈[3,4]
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Solution
The correct option is Cp∈(2,4) Roots of (p−2)x2+2(p−2)x+2=0 are not real. ⇒Δ<0 ⇒4(p−2)2−8(p−2)<0 ⇒(p−2)2−2(p−2)<0 ⇒(p−2)(p−4)<0 ∴p∈(2,4) Hence, option C.