The roots of the equation x 2- x -2-0 is-areA- -1B- -2C- 1D- 2

The correct options are A 1 C 1Given equation can be rewritten as nbsp; |x|^2+|x| 2=0 ⇒ |x|^2+2|x| |x| 2=0 ⇒ (|x|+2)(|x| 1)=0 ⇒ |x|=1 (∵|x|≥0) ∴ x= 1, 1 ...

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Standard XIII

Mathematics

Roots of a Quadratic Equation

The roots of ...

Question

The roots of the equation $x^{2} + | x | - 2 = 0$ is/are

- 1

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- 2

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1

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2

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Solution

The correct options are
A $- 1$
C $1$
Given equation can be rewritten as
$| x |^{2} + | x | - 2 = 0 \Rightarrow | x |^{2} + 2 | x | - | x | - 2 = 0 \Rightarrow (| x | + 2) (| x | - 1) = 0 \Rightarrow | x | = 1 (∵ | x | \geq 0)$
$∴ x = - 1, 1$

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Roots of a Quadratic Equation

Standard XIII Mathematics

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The roots of the equation x2+|x|−2=0 is/are

The correct options are A −1 C 1Given equation can be rewritten as |x|2+|x|−2=0⇒|x|2+2|x|−|x|−2=0⇒(|x|+2)(|x|−1)=0⇒|x|=1 (∵|x|≥0) ∴x=−1,1

The roots of the equation $x^{2} + | x | - 2 = 0$ is/are

The correct options are
A $- 1$
C $1$
Given equation can be rewritten as
$| x |^{2} + | x | - 2 = 0 \Rightarrow | x |^{2} + 2 | x | - | x | - 2 = 0 \Rightarrow (| x | + 2) (| x | - 1) = 0 \Rightarrow | x | = 1 (∵ | x | \geq 0)$
$∴ x = - 1, 1$