The roots of the equation x3 - 2x2 - 5x - 2cos x - 0 in -0- 2- is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nature of Roots of a Cubic Polynomial Using Derivatives

The roots of ...

Question

The roots of the equation $x^{3}$ + 2 $x^{2}$ + 5x + 2cos x = 0 in [0, 2 $π$ ] is

only one root

No worries! We‘ve got your back. Try BYJU‘S free classes today!

only two roots

No worries! We‘ve got your back. Try BYJU‘S free classes today!

only three roots

No worries! We‘ve got your back. Try BYJU‘S free classes today!

NO ROOTS EXIST

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

x^{3}

x^{2}

π

2 x^{2} + 5 x + 3 = 0

x^{3} - 2 x^{2} - x + 2 = 0

x^{3} + 6 x^{2} + 11 x + 6 = 0

x^{3} - 2 x^{2} - 5 x + 6 = 0; (x = 1, - 2 a n d 3)

x^{3} + x^{2} + 2 x + sin x = 0

(- 2 π, 2 π)

Join BYJU'S Learning Program