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Question

The roots of the following quadratic equation Real and unequal.
(b+c)x2 - (a + b + c) x + a = 0

A
True
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B
False
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Solution

The correct option is A True
(b+c)x2(a+b+c)x+a=0
Here, A=b+c,B=(a+b+c),C=a
D=B24AC
=[(a+b+c)]24(b+c)(a)
=a2+b2+c2+2ab+2bc+2ca4bc4ca
=a2+b2+c2+2ab2bc2ca
=(a+bc)2
D>0
We can see discriminant is greater than 0, so nature of roots are real and unequal.

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