The roots of the quadratic equation $2 (3 x + 5) (2 x - 4) = 0$ are

x = - 5, 4

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x = \frac{- 5}{6}, 1

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x = \frac{- 5}{3}, 2

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Solution

The correct option is C $x = \frac{- 5}{3}, 2$
Given: $2 (3 x + 5) (2 x - 4) = 0$
Now, the quadratic equation is in the form of product of two linear factors.
$\Rightarrow 2 (3 x + 5) (2 x - 4) = 0 \Rightarrow (3 x + 5) = 0 & (2 x - 4) = 0 \Rightarrow x = - \frac{5}{3} & x = 2$
Hence, the roots of the equation are:
$x = \frac{- 5}{3} & x = 2$

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