The roots of the quadratic equation $3 x^{2} + 2 x - 1 = 0$ are .

-1,

\frac{1}{3}

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-2,

\frac{1}{3}

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\frac{1}{3}

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2, 3

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Solution

The correct option is A -1, $\frac{1}{3}$
$3 x^{2} + 2 x - 1 = 0$
$\Rightarrow 3 x^{2} + 3 x - x - 1 = 0$
$\Rightarrow 3 x (x + 1) - 1 (x + 1) = 0$
$\Rightarrow (3 x - 1) (x + 1) = 0$
$\Rightarrow$ $(3 x - 1) = 0 o r (x + 1) = 0$
$\Rightarrow x = \frac{1}{3} o r x = - 1$
$∴$ The roots of the given equation are $- 1$ , $\frac{1}{3}$ .

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