Question

The roots of the quadratic equation $2x^2-x+\frac{1}{8}=0$ are

• A. The roots are $\frac{2}{3},\frac{3}{4}$.
• B. The roots are $\frac{1}{4},\frac{1}{4}$.
• C. The roots are $\frac{1}{2},\frac{3}{2}$.
• D. The roots are $\frac{5}{2},\frac{2}{7}$.

Answer 1

Answer: (B)

The roots are $\frac{1}{4},\frac{1}{4}$.

Given equation is $2x^2-x+\frac{1}{8}=0$

$16x^2-8x+1=0$
$16x^2-4x-4x+1=0$
$4x(4x-1)-1(4x-1)=0$
$(4x-1{)}^2=0$

$x=\frac{1}{4}$ and $x=\frac{1}{4}$