Question

The roots of the quadratic equation $p(x+a)(x-b)=0$ for all real $p,a,b\in R$ are

• A. $x=-\frac{a}{p},\frac{b}{p}$
• B. $x=a,b$
• C. $x=-a,b$

Answer 1

The correct option is C $x=-a,b$

The quadratic equation is given as:
$p(x+a)(x-b)=0\Rightarrow x+a=0\&(x-b)=0\Rightarrow x=-a\cdots \left(1\right)\&x=b\cdots \left(2\right)$
Hence, the roots of the quadratic equation are $x=-a,b$