The roots of $x^{2} + 12 x + 36 = 0$ are -

Reciprocal of each other

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Opposite of each other

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Fractionals

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Equal

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D Equal
Given: equation $x^{2} + 12 x + 36 = 0$
To find the roots of the equation
Sol:
$x^{2} + 12 x + 36 = 0 ⟹ x^{2} + 6 x + 6 x + 36 = 0 ⟹ x (x + 6) + 6 (x + 6) = 0 ⟹ (x + 6) (x + 6) = 0 ⟹ x = - 6, - 6$
Hence roots are equal.

Suggest Corrections

Similar questions

x^{2} - p x + q = 0

The equation $2^{2 x} + (a - 1) 2^{x + 1} + a = 0$ has roots reciprocal to each, then set of values of 'a' is

x^{2} + y^{2} - 4 x - 2 y - 4 = 0

x^{2} + y^{2} - 12 x - 8 y - 36 = 0

a x^{2} + b x + c = 0

a x^{2} + b x + c = 0

Join BYJU'S Learning Program