The roots of $x^{2} + 2 a x + (a^{2} - b^{2}) = 0$ are

(a - b)

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- (a + b)

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- (a - b)

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(a + b)

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Solution

The correct options are
B $- (a + b)$
C $- (a - b)$
Given,
$x^{2} + 2 a x + (a^{2} - b^{2}) = 0$
or, $x^{2} + {(a + b) + (a - b)} x + (a - b) (a + b) = 0$
or, $x (x + a + b) + (a - b) (x + a + b) = 0$
or, $(x + a + b) (x + (a - b)) = 0$
or, $x = - (a + b), - (a - b)$ .

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The roots of x2+2ax+(a2−b2)=0 are

The correct options are B −(a+b) C −(a−b)Given,x2+2ax+(a2−b2)=0or, x2+{(a+b)+(a−b)}x+(a−b)(a+b)=0or, x(x+a+b)+(a−b)(x+a+b)=0or, (x+a+b)(x+(a−b))=0or, x=−(a+b),−(a−b).

The roots of $x^{2} + 2 a x + (a^{2} - b^{2}) = 0$ are

The correct options are
B $- (a + b)$
C $- (a - b)$
Given,
$x^{2} + 2 a x + (a^{2} - b^{2}) = 0$
or, $x^{2} + {(a + b) + (a - b)} x + (a - b) (a + b) = 0$
or, $x (x + a + b) + (a - b) (x + a + b) = 0$
or, $(x + a + b) (x + (a - b)) = 0$
or, $x = - (a + b), - (a - b)$ .