The roots of $x^{2} - p x + q = 0$ are reciprocal to each other if

p = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

q = 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

p = q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p + q = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $q = 1$
The standard quadratic equation is $a x^{2} + b x + c = 0$

and Product of roots = $\frac{c}{a}$

if roots are reciprocal then the product of roots is $1$

So, for the given equation
$\frac{q}{1} = 1 ⟹ q = 1$

Suggest Corrections

Similar questions

p, q

x^{2} + p x + q = 0

p

q

x^{2} + p x + q = 0

x^{2} + p x + q = 0

x^{2} + q x + p = 0, (p \neq q)

1 + p + q = 0

x^{2} + x + p q = 0

x^{2} + p x + q = 0

if the roots of px2+qx+2=0 are reciprocal to each other then find the value of p

Join BYJU'S Learning Program