The roots of $x^{3} + x^{2} - 4 x - 4 = 0$ are

- 1, - 2, - 2

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- 1, - 2, 2

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1, - 2, 2

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- 2, 2, 4

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Solution

The correct option is B $- 1, - 2, 2$
The given equation is $x^{3} + x^{2} - 4 x - 4 = 0$
$x^{2} (x + 1) - 4 (x + 1) = 0$
$(x + 1) (x^{2} - 4) = 0$
$(x + 1) (x - 2) (x + 2)$ .... by using $(a^{2} - b^{2}) = (a - b) (a + b)$
Therefore, roots are $x = - 2, - 1, 2$

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