The roster form of the set A={x:x=n2n+1, n∈N and n<4} is ___. (Here, N stands for the set of natural numbers)
A={13,25,37}
Given, n∈N, n<4 and x=n2n+1.
where N stands for the set of natural numbers.
So, n=1,2,3.
Substituting n=1,2,3 in x=n2n+1, we get
x=12(1)+1=13,
x=22(2)+1=25 and
x=32(3)+1=37.
∴A={13,25,37}