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Question

The roster form of the set {x:x=2r+3, where r ϵ I and 2<r3}.


A

{0,1,3,5,7}

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B

{1,3,5,7,9}

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C

{0,1,3,5,7,9}

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D

{1,3,5,7}

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Solution

The correct option is B

{1,3,5,7,9}


Given 2<r3 and rϵI

So, r = -1, 0, 1, 2, 3. Also x=2r+3

Substituting r = -1, 0, 1, 2, 3 we get,

x=2(1)+3=1

x=2(0)+3=3

x=2(1)+3=5

x=2(2)+3=7

x=2(3)+3=9

The set is {1, 3, 5, 7, 9}.


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