The roster form of the set {x:x=2r+3, where r∈I and −2<r≤3}.
{1,3,5,7,9}
Given −2<r≤3 and r∈I
So, r = -1, 0, 1, 2, 3. Also x=2r+3
Substituting r = -1, 0, 1, 2, 3 we get,
x=2(−1)+3=1
x=2(0)+3=3
x=2(1)+3=5
x=2(2)+3=7
x=2(3)+3=9
⇒ The set is {1, 3, 5, 7, 9}