The roster form of the set x- x-n-2n-1- where n - N and n - 4 is -

Given n ϵ N and n lt;4 So, n = 1, 2, 3. Also, x=n/2n+1 Substituting n = 1, 2, 3 we get, x=1/2(1)+1=1/3 x=2/2(2)+1 = 2/5 x=3/2(3)+1=3/7 ∴ The required ...

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Standard VII

Mathematics

Roster Method

The roster fo...

Question

The roster form of the set ${x : x = \frac{n}{2 n + 1}, where n ϵ N and n < 4}$ is ________.

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Solution

Given $n ϵ N$ and $n < 4$

So, $n$ = 1, 2, 3.

Also, $x = \frac{n}{2 n + 1}$

Substituting $n$ = 1, 2, 3 we get,

$x = \frac{1}{2 (1) + 1} = \frac{1}{3}$

$x = \frac{2}{2 (2) + 1} = \frac{2}{5}$

$x = \frac{3}{2 (3) + 1} = \frac{3}{7}$

$∴$ The required set is ${\frac{1}{3}, \frac{2}{5}, \frac{3}{7}}$

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The roster form of the set {x:x=n2n+1,where n ϵ N and n<4} is ________.

Given n ϵ N and n<4 So, n = 1, 2, 3. Also, x=n2n+1 Substituting n = 1, 2, 3 we get, x=12(1)+1=13 x=22(2)+1=25 x=32(3)+1=37 ∴ The required set is {13,25,37}

The roster form of the set ${x : x = \frac{n}{2 n + 1}, where n ϵ N and n < 4}$ is ________.