wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

The roster form of the set {x:x=n2n+1,where n ϵ N and n<4} is ________.


A

{13,15,17}

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

{12,23,35}

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

{23,25,27}

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

{13,25,37}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

{13,25,37}


Given n ϵ N and n<4

So, n = 1, 2, 3.

Also, x=n2n+1

Substituting n = 1, 2, 3 we get,

x=12(1)+1=13

x=22(2)+1=25

x=32(3)+1=37

The required set is {13,25,37}


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sets and Their Representations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon