The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be

83 minutes

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664 minutes

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249 minutes

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Solution

The correct option is C
664 minutes

For first satellite $r_{1} = R a n d T_{1} = 83 m i n u t e$
For second satellite $r_{2} = 4 R$
$T_{2} = T_{1} (\frac{r_{2}}{r_{1}})^{\frac{3}{2}} = T_{1} (4)^{\frac{3}{2}} = 8 T_{1} = 8 \times 83 = 664 m i n u t e s$

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The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be

The correct option is C 664 minutes For first satellite r1=R and T1=83 minute For second satellite r2=4R T2=T1(r2r1)32=T1(4)32=8T1=8×83=664 minutes

The correct option is C
664 minutes

For first satellite $r_{1} = R a n d T_{1} = 83 m i n u t e$
For second satellite $r_{2} = 4 R$
$T_{2} = T_{1} (\frac{r_{2}}{r_{1}})^{\frac{3}{2}} = T_{1} (4)^{\frac{3}{2}} = 8 T_{1} = 8 \times 83 = 664 m i n u t e s$