The rotational kinetic energy of a body is $K_{r o t}$ and its moment of inertia is $I$ . The angular momentum of body is

I K_{r o t}

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2 \sqrt{I K_{r o t}}

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\sqrt{2 I K_{r o t}}

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2 I K_{r o t}

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Solution

The correct option is A $\sqrt{2 I K_{r o t}}$
Given,
$I =$ moment of inertia
The rotational kinetic energy of a body is given by
$K_{r o t} = \frac{1}{2} I ω^{2}$ , $ω =$ angular velocity
$ω = \sqrt{\frac{2 K_{r o t}}{I}}$
The angular momentum of body,
$L = I ω$
$L = I \sqrt{\frac{2 K_{r o t}}{I}}$
$L = \sqrt{2 I K_{r o t}}$ .
The correct option is C.

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