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Question

The rotor of a turbojet engine of an aircraft has a mass 180kg and polar moment of inertia 10kg m2 about the rotor axis. The rotor rotates at a constant speed of 1100 rad/s in the clockwise direction when viewed from the front of the aircraft. The aircraft while flying at a speed of 800km per hour takes a turn with a radius of 1.5 to the left. The gyroscopic moment exerted by the rotor on the aircraft structure and the direction of motion of the nose when the aircraft turns are

A
162.9 N.m, the nose goes up
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B
1629.6 N.m, the nose goes down
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C
1629.6 N.m, and the nose goes up
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D
162.9 N.m, and the nose goes down
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Solution

The correct option is B 1629.6 N.m, the nose goes down
Given data:

m=180kg

I=10kgm2

ω=1100rad/s

R=1.5m
=1500m

v=800 km/hr=800×518

=222.222m/s

ωp=vR=0.14814rad/s

Gyroscopic couple:

=I.ω.ωp×10×1100×0.14814

=1629.629Nm

Active gyroscopic couple direction clockwise in a vertical plane looking from the left side of the aircraft.

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