The runs scored by a batsman in a one-day series are respectively 32, 57, 37, 22 and 67. Find the mean score using step-deviation method using 42 as the assumed mean.

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Solution

The correct option is C 43
Number of observations, N = 5
Assumed mean, A=42

$\begin{matrix} S c o r e & D e v i a t i o n & D (X) & (X - A) & (\frac{X - A}{5}) 22 & - 20 & - 4 32 & - 10 & - 2 37 & - 5 & - 1 57 & 15 & 3 67 & 25 & 5 \sum D = 1 \end{matrix}$

$M e a n = A + \frac{\sum D}{N} \times C = 42 + \frac{1}{5} \times 5 = 43$

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The runs scored by a batsman in a one-day series are respectively 32, 57, 37, 22 and 67. Find the mean score using step-deviation method using 42 as the assumed mean.

The correct option is C 43Number of observations, N = 5 Assumed mean, A=42 ScoreDeviationD(X)(X−A)(X−A5)22−20−432−10−237−5−15715367255∑D=1 Mean=A+∑DN×C=42+15×5=43