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Question

The runs scored by two batsmen A and B in six innings are given as follows:

Batsman A

48

50

54

46

48

54

Batsman B

46

44

43

46

45

46

Determine (i) Who is a better run getter? (ii) Who is a consistent player?

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Solution

Table of calculation

Batsman A

Runs Scored

X

Deviation

D2

48

–2

4

50

0

0

54

4

16

46

–4

16

48

–2

4

54

4

16

= 300

=56

Batsman B

Runs Scored

X

Deviation

D2

46

1

1

44

–1

1

43

–2

4

46

1

1

45

0

0

46

1

1

= 270

= 8

Batsman A:

Total number of innings, N = 6

(i) Mean = = = 50

(ii) Variance = = = 9.33

(iii)

Batsman B:

Total number of innings, N = 6

(i) Mean = =

(ii) Variance = = = 1.33

(iii)

The mean score of batsman A is greater than that of batsman B.

Hence, batsman A is a better run-getter.

The coefficient of variation for batsman B is less than that for batsman A.

Hence, batsman B is more consistent.


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