Question

The runs scored by two teams A and B on the first 60 balls in a cricket match are given below

$\begin{array}{ccc}\text{Number of balls}& \text{Team A}& \text{Team B}\\ 1-6& 2& 5\\ 7-12& 1& 6\\ 13-18& 8& 2\\ 19-24& 9& 10\\ 25-30& 4& 5\\ 31-36& 5& 6\\ 37-42& 6& 3\\ 43-48& 10& 4\\ 49-54& 6& 8\\ 55-60& 2& 10\end{array}$

Represent the data of both the teams on the same graph by frequency polygons.

Answer 1

The given class intervals are not continuous. Therefore, we first modify the distribution as continuous.

$\begin{array}{cccc}\text{Number of}& \text{Class}& \text{Frequency}& \text{Frequency}\\ \text{balls}& \text{marks}& \text{Team A}& \text{Team B}\\ 0.5-6.5& 3.5& 2& 5\\ 6.5-12.5& 9.5& 1& 6\\ 12.5-18.5& 15.5& 8& 2\\ 18.5-24.5& 21.5& 9& 10\\ 24.5-30.5& 27.5& 4& 5\\ 30.5-36.5& 33.5& 5& 6\\ 36.5-42.5& 39.5& 6& 3\\ 42.5-48.5& 45.5& 10& 4\\ 48.5-54.5& 51.5& 6& 8\\ 54.5-60.5& 57.5& 2& 10\end{array}$

Now, the required frequency polygons are as shown below: