Question

The runs secored in a cirect match by $11$ players is as follows:
$9,15,121,51,101,81,50,16,82,11,11$
Find the mean, mode and median respectively of this data.

• A. $48,11,51$
• B. $49,81,11,51$
• C. $49,90,11,50$
• D. $49,81,11,50$

Answer 1

The correct option is D $49,81,11,50$

Runs scored by the players are

$9,15,121,51,101,81,50,16,82,11,11$

Mean $=\frac{9+15+121+51+101+81+50+16+82+11+11}{11}$

$=\frac{548}{11}=49.81$

Ascending order of euns is

$9,11,11,15,16,50,51,81,82,101,121$

Number of terms $=11$

$\therefore$ Median $={\left(\frac{11+1}{2}\right)}^{th}$ term $=6^{th}$ term

$=50$

The most occuring number in the given data is $11$.

So, Mode $=11$