The S-R-P for two reactions are given below AgCls-e-Ags-Claq-E-0-22V Agaq-e-Ags-E-0-80VThe solubility product of AgCl under standard conditions of temperature 298K is given by -

The correct option is A 1.6×10^ 5 Reaction will be: AgCl(S)⇌ A g ^ + (aq)+C l ^ (aq) E ^ 0 =+0.22 0.80 #160; K _ sp = e ^∧ #160; ⌈ n ...

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Solubility Product

The S.R.P for...

Question

The S.R.P for two reactions are given below $A g {C l}_{(s)} + e^{-} \to {A g}_{(s)} + {C l}_{(a q)}^{-}; E = 0.22 V$
${A g}_{(a q)}^{+} + e^{-} \to {A g}_{(s)}; E = 0.80 V$
The solubility product of $A g C l$ under standard conditions of temperature ( $298 K$ ) is given by ?

1.6 \times 10^{- 5}

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1.6 \times 10^{- 8}

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3.2 \times 10^{- 10}

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1.6 \times 10^{- 10}

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A g C l + e^{-} \to A g (s) + C l^{- 2} (a q .); E^{\circ} = 0.22 V . . . . (i)

A g^{+} (a q .) + e^{-} \to A g (s) E^{\circ} = 0.80 V . . . . (i i)

A g C l

AgCl (s) + e^{-} \to Ag (s) + C l^{-} (aq)

E^{\circ} = 0 .22V

A g^{+} (a q) + e^{-} \to A g (s)

E^{\circ} = 0 .80V

A g C l

A g C l_{(s)} + e^{-} \to A g_{(s)} + C l_{(a q)}^{-}

E^{⊖} = 0.22

A g_{(a q)}^{+} + e^{-} \to A g_{(s)}; E^{⊖} = 0.80

A g C l

A g^{+} (a q) + e^{-} \to A g (s)

E^{0} = + 0.799 V

A g C l (s) + e^{-} \to A g (s) + C l^{-} (a q)

E^{0} = + 0.222 V

1.743 \times 10^{- 10}

1.6 \times 10^{- 10}

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