The S-S bond energy is- - H f o Et-S-Et-147kJ-mol - H f o Et-S-S-Et-202kJ-mol - H f o Sg-223kJ-mol

The correct option is D 278 kJ C_2H_5 S C_2H_5+S(s)→C_2H_5 S S C_2H_5 Δ H _ reaction =∑Δ H _ f(products) ^ o +∑Δ H _ f(reactants) ^ o =( 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Enthalpy

The S-S bon...

Question

The $S - S$ bond energy is:
$Δ H_{f}^{o} (E t - S - E t) = - 147 k J / m o l$
$Δ H_{f}^{o} (E t - S - S - E t) = - 202 k J / m o l$
$Δ H_{f}^{o} S (g) = + 223 k J / m o l$

168 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

126 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

278 k J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

575 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $278 k J$
$C_{2} H_{5} - S - C_{2} H_{5} + S (s) \to C_{2} H_{5} - S - S - C_{2} H_{5}$
$Δ H_{r e a c t i o n} = \sum {Δ H}_{f (p r o d u c t s)}^{o} + \sum Δ H_{f (r e a c t a n t s)}^{o}$
$= (- 202) - (- 147) = - 55 k J$
$Δ H_{r e a c t i o n} = \sum {B E}_{r e a c t a n t s} - \sum {B E}_{p r o d u c t s}$
$- 55 =$ Heat of sublimation or enthalpy of atomisation of sulphur $- B E (S - S)$
$- 55 = 223 - B E (S - S)$
$B E (S - S) = 223 + 55 = 278 k J$

Suggest Corrections

Similar questions

From the following information, calculate cash from operating activities:
$\begin{matrix} Rs. Proft and Loss Balance on 1st April, 2017 & 25, 000 Profit and Loss Balance on 31st March, 2018 & 80, 000 Depreciation on Fixed Assets & 12, 500 Amortisation of Goodwill & 8, 000 Loss on Sale of Machine & 20, 000 Provision for Taxation & 15, 000 Transfer to General Reserve & 30, 000 Decrease in Trade Receivables & 22, 800 Decrease in Trade Payables & 4, 700 Outstanding Expenses on 1st April, 2017 & 5, 000 Outstanding Expenses on 31st March, 2018 & 6, 500 Prepaid Expenses on 1st April, 2017 & 2, 000 \end{matrix}$

Q. For the following data calculate lattice energy of

A B (s)

A (s) \to A^{+} (g) + e - 610 k J / m o l

B (s) + e \to B^{-} (g) + - 260 k J / m o l

A (s) + B (g) \to A B (s) - - 569 k J / m o l

Q. For the given reaction

H_{2} (g) + S (s) ⟶ H_{2} S (g); Δ H_{T} = 100 k J / m o l

and

Δ S_{T} = 400 J / m o l / K

Temperature at which above reaction occurs reversibly is (Assuming

Δ H_{T}

and

Δ S_{T}

are independent of temperature)

Ron recorded the letters of the alphabet in a sentence with the following results:

T H E S U N S E T S I N T H E W E S T

The sum of the frequencies of all the vowels is ______.

For a first order reaction A ⟶ P, the temperature (T) dependent rate constant (k) was found to follow the equation log k = -2000(1/T) + 6.0. The pre-exponential factor A and the activation energy $E_{a},$ respectively, are

(IIT-JEE, 2009)

Join BYJU'S Learning Program

The S−S bond energy is: ΔHof(Et−S−Et)=−147kJ/molΔHof(Et−S−S−Et)=−202kJ/molΔHofS(g)=+223kJ/mol

The $S - S$ bond energy is:
$Δ H_{f}^{o} (E t - S - E t) = - 147 k J / m o l$
$Δ H_{f}^{o} (E t - S - S - E t) = - 202 k J / m o l$
$Δ H_{f}^{o} S (g) = + 223 k J / m o l$