The same amount of electric current is passed through the solutions of $A g N O_{3}$ and $H C l$ . If $1.08$ g of silver is obtained from $A g N O_{3}$ solution, the amount of hydrogen liberated at STP will be:

1.008

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11.2

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0.01

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1.1

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Solution

The correct option is C $0.01$ g
Faraday's second law of electrolysis states that, when the same quantity of electricity is passed through several electrolytes, the mass of the substances deposited are proportional to their respective chemical equivalent or equivalent weight.
According to Faraday's second law,
$\frac{W_{H_{2}}}{W_{A g}} = \frac{E_{H_{2}}}{E_{A g}}$
$⟹ W_{H_{2}} = \frac{1}{108} \times 1.08 = 0.01 g$

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