The same mass of aluminium is drawn into two wires 1mm and 2mm thick.The two wires are connected in series and current is passed through them.Heat produced in wire is in the ratio

1)16/1

2)8/32

3)8/2

4)4/2

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Solution

H=i^2 RT =i^2 (pl/A)T
=i^2( pVT/A^2)

{ p=density of metal
l = length of wire
A= area of wire
T= temperature
Also V= Al
Ie, l= V/A }

From above H is inversley propotionalp to square of area
Ie , H is inversely propotional to r^4

Ie H1 / H2. = r2 ^4 / r1 ^4.
= 2^4 /1^4 = 16/1

answer is A 16:1

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The same mass of aluminium is drawn into two wires 1mm and 2mm thick.The two wires are connected in series and current is passed through them.Heat produced in wire is in the ratio 1)16/1 2)8/32 3)8/2 4)4/2

H=i^2 RT =i^2 (pl/A)T =i^2( pVT/A^2) { p=density of metal l = length of wire A= area of wire T= temperature Also V= Al Ie, l= V/A } From above H is inversley propotionalp to square of area Ie , H is inversely propotional to r^4 Ie H1 / H2. = r2 ^4 / r1 ^4. = 2^4 /1^4 = 16/1 answer is A 16:1

The same mass of aluminium is drawn into two wires 1mm and 2mm thick.The two wires are connected in series and current is passed through them.Heat produced in wire is in the ratio

1)16/1

2)8/32

3)8/2

4)4/2

H=i^2 RT =i^2 (pl/A)T
=i^2( pVT/A^2)

{ p=density of metal
l = length of wire
A= area of wire
T= temperature
Also V= Al
Ie, l= V/A }

From above H is inversley propotionalp to square of area
Ie , H is inversely propotional to r^4

Ie H1 / H2. = r2 ^4 / r1 ^4.
= 2^4 /1^4 = 16/1

answer is A 16:1