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Standard XII

Chemistry

Faraday's First Law

The same quan...

Question

The same quantity of electricity is passed through 0.1M $H_{2} S O_{4}$ and 0.1M $H C l$ . The amounts of $H_{2}$ obtained at the cathode are in ratio:

1:1

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2:1

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1:2

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3:1

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Solution

The correct option is A 1:1
In both cases $H^{+}$ is reduced
$∴$ same amount of electricity can reduce an equal amount of $H^{+}$ from both solutions
$∴$ Amount of $H_{2}$ liberated in equal
$∴$ Ratio is 1 : 1

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Similar questions

Q. The same quantity of electricity is passed through

H_{2} S O_{4}

and

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Q. On passing electricity through dil.

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The same quantity of electricity is passed through 0.1M H2SO4 and 0.1M HCl. The amounts of H2 obtained at the cathode are in ratio:

The correct option is A 1:1In both cases H+ is reduced∴ same amount of electricity can reduce an equal amount of H+ from both solutions∴ Amount of H2 liberated in equal∴ Ratio is 1 : 1

The same quantity of electricity is passed through 0.1M $H_{2} S O_{4}$ and 0.1M $H C l$ . The amounts of $H_{2}$ obtained at the cathode are in ratio:

The correct option is A 1:1
In both cases $H^{+}$ is reduced
$∴$ same amount of electricity can reduce an equal amount of $H^{+}$ from both solutions
$∴$ Amount of $H_{2}$ liberated in equal
$∴$ Ratio is 1 : 1