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Question

The same quantity of electricity that liberated 2.158 g silver was passed through a solution of a gold salt and 1.314 g of gold was deposited. The equivalent mass of silver is 107.9. Calculate the equivalent mass of gold. What is the oxidation state of gold in this gold salt? (At. mass of gold =197).

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Solution

Given:-
Mass of SIlver(m1)=2.158g
Mass of gold(m2)=1.314g
Equivalent mass of Ag(E1)=107.9
Equivalent mass of Au(E2)=?
Formula:-
m1m2=E1E2
2.1581.314=107.9E2
E2=107.9×1.3142.158=65.7
Equivalent weight of Gold=AtomicmassValency
Valency=AtomicmassE2=19765.7=3
Oxidation state of Gold=3.

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