The correct option is C {H1,H2,H3,H4,H5,H6,T}
Since either coin can turn up Head (H) or Tail (T), these are the possible outcomes for the coin tossed.
Let us assume that 1,2,3,4,5 and 6 are possible number that come when the die is thrown.
When head is encountered, then, number of elements in sample space =(1×6)=6
∴ Sample space in case head is encoutered is, SH={H1,H2,H3,H4,H5,H6}
Now, when tail is encountered sample space ST={T}
Therefore the total sample space S={H1,H2,H3,H4,H5,H6,T}