The scale of a galvanometer of resistance 100 - contains 25 divisions- It gives a deflection of one division on passing a current of 4 - 10-4 A- The resistance in ohms to be added to it- so that it may become a voltmeter of range 2-5 volt isA- 100B- 150C- 300D- 250

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Question

The scale of a galvanometer of resistance $100 Ω$ contains 25 divisions. It gives a deflection of one division on passing a current of $4 \times 10^{- 4} A$ . The resistance in ohms to be added to it, so that it may become a voltmeter of range 2.5 volt is

100

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150

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250

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300

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Solution

The correct option is B 150
Current sensitivity of galvanometer $= 4 \times 10^{- 4}$ Amp/div.
So full scale deflection current $(i_{g}) = C u r r e n t s e n s i t i v i t y \times T o t a l n u m b e r o f d i v i s i o n = 4 \times 10^{- 4} \times 25 = 10^{- 2} A$
To convert galvanometer in to voltmeter, resistance to be put in series is
$R = \frac{V}{i_{g}} - G = \frac{2.5}{10^{- 2}} - 100 = 150 Ω$

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The scale of a galvanometer of resistance 100Ω contains 25 divisions. It gives a deflection of one division on passing a current of 4×10−4 A. The resistance in ohms to be added to it, so that it may become a voltmeter of range 2.5 volt is

The correct option is B 150Current sensitivity of galvanometer =4×10−4 Amp/div. So full scale deflection current (ig)=Current sensitivity×Total number of division=4×10−4×25=10−2 A To convert galvanometer in to voltmeter, resistance to be put in series is R=Vig−G=2.510−2−100=150Ω

The scale of a galvanometer of resistance $100 Ω$ contains 25 divisions. It gives a deflection of one division on passing a current of $4 \times 10^{- 4} A$ . The resistance in ohms to be added to it, so that it may become a voltmeter of range 2.5 volt is