The scale of a galvanometer of resistance 100- contains 25 divisions- It gives a deflection of one division on passing a current of 4 - 10-4 amperes- The resistance in ohms to be added to it- so that it may become a voltmeter of range 2-5V is

A galvanometer, whose resistance is 50 ohm, has 25 division in it. When a current of $4 \times 10^{- 4} A$ passes through it, is its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range $2.5 V,$ it should be connected to a resistance of:

Join BYJU'S Learning Program

The scale of a galvanometer of resistance 100Ω contains 25 divisions. It gives a deflection of one division on passing a current of 4×10−4 amperes. The resistance in ohms to be added to it, so that it may become a voltmeter of range 2.5V is

The correct option is B 150V=ig(G+R)R=Vig−GR=2.54×10−4×25−100R=250−100R=150

The scale of a galvanometer of resistance $100 Ω$ contains $25$ divisions. It gives a deflection of one division on passing a current of $4 \times 10^{- 4}$ amperes. The resistance in ohms to be added to it, so that it may become a voltmeter of range $2.5 V$ is

The correct option is B $150$
$V = i_{g} (G + R)$
$R = \frac{V}{i_{g}} - G$
$R = \frac{2.5}{4 \times 10^{- 4} \times 25} - 100$
$R = 250 - 100$
$R = 150$