The scale of a spring balance reading from 0 to 10kg is 0.25m long. A body suspended from the balance oscillates vertically with a period of π/10s. The mass suspended is neglected then the mass of the spring is:
A
10kg
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B
0.98kg
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C
5kg
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D
20kg
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Solution
The correct option is B0.98kg Time period T =2π√mk=0.1×π Angular velocity ω=2πT=20rad/s for 'k' the spring constant at maximum reading x=0.25 m extension: M=10kg Mg=−kx k- spring constant ; g -acceleration due to gravity k=392.4N/m Now 2π√mk=0.1×π putting the value of k . m=0.98kg