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Question

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of π/10 s. The mass suspended is neglected then the mass of the spring is:

A
10 kg
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B
0.98 kg
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C
5 kg
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D
20 kg
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Solution

The correct option is B 0.98 kg
Time period T =2πmk=0.1×π
Angular velocity ω=2πT=20rad/s
for 'k' the spring constant at maximum reading x=0.25 m extension:
M=10kg
Mg=kx
k- spring constant ; g -acceleration due to gravity
k=392.4N/m
Now

2πmk=0.1×π
putting the value of k .
m=0.98kg

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