wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The scale of a spring balance reading from 0 to 10 kg is 0.25 m long. A body suspended from the balance oscillates vertically with a period of π/10 s. The mass suspended is neglected then the mass of the spring is:

A
10 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.98 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.98 kg
Time period T =2πmk=0.1×π
Angular velocity ω=2πT=20rad/s
for 'k' the spring constant at maximum reading x=0.25 m extension:
M=10kg
Mg=kx
k- spring constant ; g -acceleration due to gravity
k=392.4N/m
Now

2πmk=0.1×π
putting the value of k .
m=0.98kg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Expression for SHM
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon