Question

# The scale of uniform mass of 1 kg as shown below is in equilibrium. The mass m suspeneded at 90cm mark has a mass of .433.33 grams533.33 grams333.33 grams233.33 grams

Solution

## The correct option is C 333.33 grams The weight of the meter scale will be acting at its mid-point, i.e., at 50 cm mark. We calculate the torque about the fulcrum, i.e. the 60 cm mark. By the principle of moments, Torque of the weight of the rod = Torque of the uniform mass at 90 cm mark  1000×g×(60−50) cm =m×g×(90−60) cm or, 10000 = 30 m or, m = 333.33 grams.

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