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Question

The scale of uniform mass of 1 kg as shown below is in equilibrium. The mass m suspeneded at 90cm mark has a mass of .
  1. 433.33 grams
  2. 533.33 grams
  3. 333.33 grams
  4. 233.33 grams


Solution

The correct option is C 333.33 grams

 The weight of the meter scale will be acting at its mid-point, i.e., at 50 cm mark.
We calculate the torque about the fulcrum, i.e. the 60 cm mark.
By the principle of moments,
Torque of the weight of the rod = Torque of the uniform mass at 90 cm mark 
1000×g×(6050) cm =m×g×(9060) cm
or, 10000 = 30 m
or, m = 333.33 grams.

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