The correct option is C 0.00864 cm
We know that,
At high temperatures, actual reading is more than the scale reading. To find the error in the reading, we will use the formula
α=(1L)(ΔLΔT)
Then, error in reading =ΔL
=scale reading (L)×α×ΔT
=(60)(1.2×10−5)(27∘C−15∘C)
=0.00864 cm