The Schrodinger equation for a free electron of mass m and energy E written in terms of the wave function ψ is d2ψdx2+8π2mEh2ψ=0. The dimensions of the coefficient of ψ in the second term must be
A
[M1L1]
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B
[L−2]
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C
[L−3/2]
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D
[M1L−1T1]
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Solution
The correct option is B[L−2] The quantity whose dimension is to be determined Q=8π2mEh2 We know, dimension of mass m=[M] Dimension of energy E=[ML2T−2] Dimension ofPlanck's constant h=[ML2T−1] Thus dimensions of Q=[M][ML2T−2][ML2T−1]2=[L−2]